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Efficiency of the engine in the above qu...

Efficiency of the engine in the above questions is

A

`30%`

B

`10%`

C

`20%`

D

`80%`

Text Solution

Verified by Experts

The correct Answer is:
C
`eta= 1-(T_(2))/(T_(1))= 1-(400)/(500)= 1/5= 20%`
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Carnot engine is an ideal heat engine, which converts heat energy into mechanical energy. Efficiency of Carnot engine is given by eta =1 - (T_2 // T_1) , where T_1 is temperature of source and T_1 , is temperature of sink. If Q_1 is the amount of heat absorbed/cycle from the source, Q_2 is the amount of heat rejected/cycle to the sink and W is the amount of useful work done/cycle, then W= Q_1 -Q_2 and (Q_2)/(Q_1) = (T_2)/(T_1) Efficiency of the engine in the above question is .if source and sink temperature respectively 227 and 127 .

Work done //cycle by the engine in the above questions is

Efficiency of heat engine is defined as the

Efficiency of Carnot engine is 100% if

Assertion: Efficiency of a heat engine can't be greater than efficiency of Carnot engine. Reason: Effieciency of any engine is never 100%

Assertion : The efficiency of a heat engine can never be unity. Reason : Efficiency of heat engine is fundamental limitation given by first law of thermodynamics.

Efficiency of a Carnot heat engine may be given as

A : Efficiency of heat engine can neve be 100%. R : Second law of thermodynamics puts a limitaion of the efficiency of a heat engine.

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