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At what temperature , will the rms speed...

At what temperature , will the rms speed of oxygen molecules be sufficient for escaping from the earth ? `Taken m = 2.76 xx 10^(-26) kg, k = 1.38 xx 10^(-23) J//K and v_(e) = 11.2 km//s`.

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To find the temperature at which the root mean square (rms) speed of oxygen molecules is sufficient for escaping from the Earth, we can use the relationship between kinetic energy and escape velocity. The steps to solve this problem are as follows: ### Step-by-Step Solution: 1. **Understand the Concept**: The rms speed of a gas molecule must be equal to or greater than the escape velocity for the molecule to escape Earth's gravitational pull. The escape velocity \( v_e \) is given as \( 11.2 \, \text{km/s} \). 2. **Convert Escape Velocity**: Convert the escape velocity from km/s to m/s: \[ ...
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