Home
Class 11
PHYSICS
The molecules of a given mass of gas hav...

The molecules of a given mass of gas have a rms velocity of `200 m//sec at 127^(@)C and 1.0 xx 10^(5) N//m^(2)` pressure. When the temperature is `127^(@)C` and pressure is `0.5 xx 10^(5) N//m^(2)` the rms velocity in `m//sec` will be

Text Solution

Verified by Experts

Here, `upsilon_(1) = 200m//s`
`T_(1) = 27^(@)C = (27+273)K = 300K`
`P_(1) = 1 xx 10^(5) N//m^(2)`
`T_(2) = 127^(@)C = (127 + 273)K = 400K`
`P_(2) = 0.5 xx 10^(5) N//m^(2) . Upsilon_(2)=?`
As is known rms velocity of gas molecules does not depend upon pressure, and
`upsilon prop sqrt(T)`
`:. (upsilon_2)/(upsilon_1) = sqrt((T_2)/(T_1))`
`upsilon_(2) = upsilon_(1) sqrt((T_2)/(T_1)) = 200 xx sqrt((400)/(300)) = (200 xx 2)/(sqrt(3)) m//s`
`upsilon_(2) = 230.9 m//s`.
Promotional Banner

Topper's Solved these Questions

  • BEHAVIOUR OF PERFECT GAS & KINETIC THEORY

    PRADEEP|Exercise NCERT questions|13 Videos
  • BEHAVIOUR OF PERFECT GAS & KINETIC THEORY

    PRADEEP|Exercise Higher order thinking skills questions|9 Videos
  • BEHAVIOUR OF PERFECT GAS & KINETIC THEORY

    PRADEEP|Exercise Long answer questions|13 Videos
  • GRAVIATION

    PRADEEP|Exercise Assertion-Reason Type Questions|19 Videos

Similar Questions

Explore conceptually related problems

The molecules of a given mass of a gas have rms velocity of 200 m//s at 27^(@)C and 1.0 xx 10^(5) N//m_(2) pressure. When the temperature and pressure of the gas are respectively 127^(@)C and 0.05 xx 10^(5) Nm^(-2) , the rms velocity of its molecules in ms^(-1) is

The molecules of a given mass of gas have an rms velocity of 200 ms(-1) at 27^@C and pressure 1 atm. When the temperature is 127^@C and pressure is 2 atm, the rms velocity in m s^(-1) will be ?

The molecule of a given mas of gas have r.m.s. speed 200 ms^(-1) at 27^(@)C and 10^(5)Nm^(-2) pressure. When the absolute temperature is doubled and the pressure is halved, then find rms speed of the molecules of the same gas.

The rms velocity molecules of a gas of density 4 kg m^(-3) and pressure 1.2 xx 10^(5) N m^(-2) is

One bar is equivalent of 10^(5)N//m^(2) . The atmosphere pressure is 1.0313xx10^(5)N//m^(2) . The same in bar is

Calculate the rms velocity of molecules of a gas of density 1.5 g litre^(-1) at a pressure of 2 xx 10^(6) N//m^(2) .