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A vessel contains 28 g of N(2) and 32 g ...

A vessel contains `28 g of N_(2) and 32 g of O_(2)` at temperature T = 1800 K and pressure 2 atm. What would be the pressure when `N_(2)` dissociates 30% and `O_(2)` dissociates 50% and temperature remains constant ?

Text Solution

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If `P_(1) . P_(2) ` are partial pressures of `N_(2) and O_(2)` then
`P_(i) = P_(1) + P_(2) = ((m_1)/(M_1)) (RT)/(V) + ((m_2)/(M_2))(RT)/(V) = (2RT)/(V)`
`P_(f) =(70/100 xx 28/28 (RT)/(V) + 30/100 xx 28/14 (RT)/(V))+`
`(50/100 xx 32/32 (RT)/(V) + 50/100 xx 32/16 (RT)/(V)) = 2.8 (RT)/(V)`
`P_(f) = 1.4 P_(i) = 1.4 xx 2 atm = 2.8 atm`.
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