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The density of water is 10^(3) kg//m^(3)...

The density of water is `10^(3) kg//m^(3)`. Estimate the size `("in" Å)` of a water molecule.

Text Solution

Verified by Experts

The correct Answer is:
2
One mole of water has a mass = `2+16 18 g`
`=0.018 kg`.
`:.` Mass of one molecules of water `= (0.018)/(6xx10^(23))`
`=3xx10^(-26)kg`
Volume of water molecule `= ("mass")/("density") = (3 xx 10^(-26))/(10^(3))`
`V = 3 xx 10^(-29) m^(3)`
If `r` is radius of water molecule, then
`V = 4/3 pi r^(3) = 3 xx 10^(-29)`
`r = [(3xx3xx10^(-29))/(4xx3.14)]^(1//3) = 2 xx 10^(-10) m = 2 Å`.
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Knowledge Check

  • The approximate depth of an ocean is 2700 m. The compressibility of water is 45.4 xx 10^(-11) Pa^(-1) and density of water is 10^(3) kg//m^(3) . What fractional compression of water will be obtained at the bottom of the ocean ?

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