Home
Class 11
PHYSICS
A particle executes SHM given by y=0.24s...

A particle executes SHM given by `y=0.24sin(400t+0.5)` in SI units. Find `(i)` amplitude `(ii)` frequency and `(iii)` time period of vibration.

Text Solution

AI Generated Solution

To solve the problem step by step, we will analyze the given equation of simple harmonic motion (SHM) and extract the required parameters: amplitude, frequency, and time period. ### Given: The equation of SHM is: \[ y = 0.24 \sin(400t + 0.5) \] ### Step 1: Find the Amplitude The amplitude \( A \) of the SHM can be directly obtained from the equation. The general form of the SHM equation is: ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • OSCILLATIONS AND WAVES

    PRADEEP|Exercise conceptual problems|84 Videos

  • OSCILLATIONS AND WAVES

    PRADEEP|Exercise Very Short Answer Questions|99 Videos

  • OSCILLATIONS AND WAVES

    PRADEEP|Exercise CURIOSITY QUESTION|2 Videos

  • MATHEMATICAL TOOLS

    PRADEEP|Exercise Fill in the blanks|5 Videos

  • PHYSICAL WORLD AND MEASUREMENT

    PRADEEP|Exercise Competiton Focus Jee Medical Entrance|18 Videos

Similar Questions

Explore conceptually related problems

A particle executes SHM represented by the equation, y = 0.02 sin (3.14t+(pi)/(2))m . Find (i) amplitude (ii) time period (iii) frequecy (iv) epoch (v) maximum velocity and (vi) maximum acceleration.

The displacement of a particle executing SHM is given by y=0.2sin50pi(t+0.01) metre Calculate the amplitude,t he period, maximum velocity and the displacement at the start of the motion.

Knowledge Check

  • A particle executes a linear S.H.M. given by y= 0.5 "sin" 100 (metre). Its amplitude and frequency given in cm and hertz are

    A
    50 cm and 100 Hz
    B
    5 cm and 50 Hz
    C
    50 cm and `(50)/(pi)Hz`
    D
    `0.5 " and " (pi)/(50)Hz`

  • If the displacement of a particle executing SHM is given by y=0.30 sin (220t +0.64) in metre , then the frequency and maximum velocity of the particle is

    A
    35 Hz , 66 m / s
    B
    45 Hz , 66 m / s
    C
    58 Hz , 113 m / s
    D
    35 Hz, 132 m/s

  • The motion of a particle executing S.H.M. is given by x= 0.01 sin 100 pi (t+.05) , where x is in metres and time is in seconds. The time period is

    A
    0.01 sec
    B
    0.02 sec
    C
    0.1 sec
    D
    0.2 sec

    • Similar Questions

    Explore conceptually related problems

    A simple harmonic oscillation is represented by the equation. y=0.40sin(440t+0.61) Here y and t are in m are s respectively. What are the values of (i) amplitude (ii) angular frequency (iii) frequency of oscillations (iv) time period of oscillations and (v) initial phase?

    The following equation gives the displacement u at time t for a particle at a distance x: y=0.01 sin 500pi(t-x//30) where all are in SI units. Find (i) the wavelength, (ii) the speed of the wave, (iii) the velocity amplitude of the particle of the medium and (iv) the accelration amplitude of the particle of the medium.

    A particle executed SHM iwht a time period of 3s and amplitude 6cm. Find (i) displacement (ii) velocity and (iii) acceleration, after 1//2 second, starting from the mean position.

    The displacement of a particle executing S.H.M. is given by x = 0.34 sin (300 t + 0.68)m. Then its frequency is

    A particle executes S.H.M. given by the equation y = 0.45 sin 2t where y is in meter and t is in second. What is the speed of the particle when its displacement is 7.5 cm?

    Home
    Profile