Maximum velocity of a particle in SHM is `16cm^(-1)` . What is the average velocity during motion from one extreme position to other extreme position?

Explanation

Given, Max. velocity `=aomega=16cms^(-1)`
or `a(2pi)/(T)=16 or (a)/(T)=(1)/(2pi)`
Average velocity,
`v_(av)=(t otal displacement)/(t otal ti me)=(2a)/(T//2)=(4a)/(T)`
`:.v_(av)=4xx(16)/(2pi)=(32)/(pi)cms^(-1)`.