A linear harmonic oscillator of force constant `2 xx 10^6 N//m` and amplitude (0.01 m) has a total mechanical energy of (160 J). Its.

Explanation

Here, `k=2xx10^(6)Nm^(-1)`,
`a=2cm =0.02m` ltbtgt Total energy `=600J`
As maximum K.E. `=`max. P.E. `=(1)/(2)ka^(2)`
`=(1)/(2)xx(2xx10^(6))xx(0.02)^(2)=400J`
In SHM P.E. is minimum at the mean position and K.E. is maximum at the mean position, whereas total meachanical energy is constant throughout. Therefore, at mean position total mechnaical energy `=max K.E.+min. P.E.`
or `600=400+min. P.E.`
or min. P.E.` =600-400=200J`