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A block whose mass is 1 kg is fastened t...

A block whose mass is 1 kg is fastened to a spring.The spring has a spring constant `50Nm^(-1)`. The block is pulled to a distance `x=10cm` from its equilibrium position at `x=0` on a frictionless surface at `t=0`. Calculate the kinetic, potential and total energies of the blocak when it is 5cm away from the mean position.

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To solve the problem, we need to calculate the kinetic energy (KE), potential energy (PE), and total energy (TE) of a block attached to a spring when it is 5 cm away from the mean position. Here are the steps: ### Step 1: Identify the given values - Mass of the block, \( m = 1 \, \text{kg} \) - Spring constant, \( k = 50 \, \text{N/m} \) - Initial displacement from equilibrium (amplitude), \( A = 10 \, \text{cm} = 0.1 \, \text{m} \) - Displacement from equilibrium at the time of interest, \( x = 5 \, \text{cm} = 0.05 \, \text{m} \) ...
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