A second pendulum is takin in a carriage. Find the period of oscillation when the carriage moves with an acceleration of `4*2ms^(-2)` (i) vertically upwards (ii) vertically downwards and (ii) in a horizontal direction.

Explanation

To find the period of oscillation of a second pendulum in a carriage moving with an acceleration of \(4.2 \, \text{m/s}^2\) in different directions, we will use the formula for the period of a pendulum:

\[ T = 2\pi \sqrt{\frac{L}{g_{\text{effective}}}} \]

where \(L\) is the length of the pendulum and \(g_{\text{effective}}\) is the effective acceleration due to gravity.

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