The frequency of oscillation of a mass m suspended by a spring is `v_(1)`. If the length of the spring is cut to on-half, the same mass oscillates with frequency `v_(2)`. Determing the value of `v_(2)//v_(1)`.

Explanation

To solve the problem, we need to determine the ratio of the frequencies of oscillation of a mass suspended from a spring before and after the spring is cut in half.

### Step-by-Step Solution:

1. **Understanding the Frequency of Oscillation**:
The frequency of oscillation \( v \) of a mass \( m \) suspended from a spring with spring constant \( k \) is given by the formula:
\[
v = \frac{1}{2\pi} \sqrt{\frac{k}{m}}
...