The motion of a particle in S.H.M. is described by the displacement function, `x=Acos(omegat+phi)`, If the initial `(t=0)` position of the particle is 1cm and its initial velocity is `omega cm s^(-1)`, what are its amplitude and initial phase angle ? The angular frequency of the particle is `pis^(-1)`. If instead of the cosine function, we choos the sine function to describe the SHM`: x=B sin(omegat+alpha)`, what are the amlitude and intial phase of the particle with the above intial conditions ?

Explanation

To solve the problem, we need to find the amplitude and initial phase angle of a particle in Simple Harmonic Motion (SHM) described by the displacement function \( x = A \cos(\omega t + \phi) \) given the initial conditions. We will also find the amplitude and initial phase angle when using the sine function instead.

### Step-by-Step Solution

**Step 1: Identify Given Values**
- Initial position \( x(0) = 1 \, \text{cm} \)
- Initial velocity \( v(0) = \omega \, \text{cm/s} \)
- Angular frequency \( \omega = \pi \, \text{s}^{-1} \)
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