The piston in the cylinder head of a locomotive has a stroke (twice the amplitude) of 1.0m. If the piston moves with simple harmonic motion with an angular frequency of `200rev//`min., what is its maximum speed ?

Explanation

To solve the problem, we need to find the maximum speed of the piston moving in simple harmonic motion (SHM). Here are the steps to arrive at the solution:

### Step 1: Understand the relationship between stroke and amplitude
The stroke of the piston is given as 1.0 m. The stroke is defined as twice the amplitude (A) of the motion. Therefore, we can find the amplitude:
\[ \text{Stroke} = 2A \implies A = \frac{\text{Stroke}}{2} = \frac{1.0 \, \text{m}}{2} = 0.5 \, \text{m} \]

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