Two sitar strings A and B playing the note 'Ga' are slightly out of tune and produce beats of frequency 6 Hz. The tension in the string A is slightly reduced and the beat frequency is found to reduce to 3 Hz. If the original frequency of A is 324 Hz, what is the frequency of B?

Explanation

To solve the problem, we need to find the frequency of string B given the information about the beat frequencies and the original frequency of string A. Let's break down the solution step by step.

### Step 1: Understand the relationship between the frequencies
The beat frequency is the absolute difference between the frequencies of the two strings. If the original frequency of string A is \( N_A \) and the frequency of string B is \( N_B \), then the beat frequency \( f_b \) can be expressed as:
\[ f_b = |N_A - N_B| \]
Given that the beat frequency is initially 6 Hz, we can write:
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