A tuning fork vibrating with a frequency of 512 Hz is kept close to the open end of a tube filled with water , figure. The water level in the tube is gradually lowerd. When the water level is 17cm below the open end, maximum intensity of sound in heard. If the room temperature is `20^(@)C`, calculate
(a) speed of sound in air at room temperature.
(b) speed of sound in air at `0^(@)C`
(c) if the water in the tube is replaced with mercury, will there be any difference in your observations?

Explanation

Here, `v=512Hs, l_(1)=17cm`
(a) From `v=(upsilon_(t))/(4l_(1))`
`upsilon_(t)=v(4l_(1))=512((4xx17)/(100))m//s=348.16m//s`
(b) `upsilon_(0)=upsilon_(t)sqrt((T_(0))/(T))=348.16sqrt((273+0)/(273+20))=336.1m//s`
(c) There will be no change in resonance length when water is replaced by mercury as it serves as reflector of sound waves only. The intensity of sound may increase because mercury beign denser than water will reflect sound waves more completely.