The corrected Newton's formula for velocity of sound in air is `v=sqrt((gamma P)/(rho))`, where P is pressure and `rho` is density of air, `gamma =1.42` for air. At normal temperature ane pressure, velocity of sound in air `=332m//s`.
Read the above passage and answer the following question:
(i) How do the sound horns protect us from the oncoming vehicles ? ltbr. (ii) How does a sand scorpion fing its prey?
(iii) Will the velocity of sound in air change on changing the pressure alone?

Explanation

(i) At N.T.P., velocity of sound in air `=332m//s=(332//1000km)/(1//6xx60hr)=(332)/(1000)xx3600km//hr=1195km//hr` which is greater than velocity of fastest car, bus , train and even an aeroplane. Therefore, sound of horn of vehicle will reach our ears before the vehicle reaches us. Therefore, we are protected.
(ii) The sand scorption finds its prey, the beetl, because the beetal's motion sends fast longitudinal waves along the sand's surface. The sand scorpion intercepts the longitudinal waves and learns the direction of the beetal. The sand scorpion turns in this direction and finds its prey.
(iii) No. This is because when P alone is changes , `rho` changes so as to keep `(P//rho)` constant. Therefore ,
`v=sqrt(gammaP//rho)`= constant.