Home
Class 11
PHYSICS
A simple harmonic motion is represented ...

A simple harmonic motion is represented by
`x=10sin(20t+0.5).`
Write down its amplitude, angular frequency, frequency, time period and initial phase if displacement is measured in metres and time seconds.

Text Solution

AI Generated Solution

To solve the problem, we will analyze the given equation of simple harmonic motion (SHM) and extract the required parameters step by step. Given the equation of SHM: \[ x = 10 \sin(20t + 0.5) \] ### Step 1: Identify the Amplitude The amplitude \( r \) is the coefficient of the sine function in the SHM equation. - From the equation, we see that the amplitude \( r = 10 \) meters. ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • OSCILLATIONS AND WAVES

    PRADEEP|Exercise Multiple Choice Question-I|21 Videos
  • OSCILLATIONS AND WAVES

    PRADEEP|Exercise Multiple Choice Question-II|14 Videos
  • OSCILLATIONS AND WAVES

    PRADEEP|Exercise Fill In The Blanks|20 Videos
  • MATHEMATICAL TOOLS

    PRADEEP|Exercise Fill in the blanks|5 Videos
  • PHYSICAL WORLD AND MEASUREMENT

    PRADEEP|Exercise Competiton Focus Jee Medical Entrance|18 Videos

Similar Questions

Explore conceptually related problems

A simple harmonic motion is represented by x = 5 sin (10t + 0.25) Determine is (i) amplitude (ii) Angular frequency (iii) Frequency (iv) Time period (v) Initial phase [Displacement is measured in metres and time in seconds]

A simple harmonic motion is represented by F(t)=10sin(20t+0.5) . The amplitude of the S.H.M. is

Knowledge Check

  • A simple harmonic motion is represented by x(t) = sin^(2)omega t - 2 cos^(2) omega t . The angular frequency of oscillation is given by

    A
    `omega`
    B
    `2 omega`
    C
    `4 omega`
    D
    `omega/2`
  • A simple harmonic motion is represented by x(t) = sin^2 omegat - 2 cos^(2) omegat . The angular frequency of oscillation is given by

    A
    `omega`
    B
    `2 omega`
    C
    `4 omega`
    D
    `(omega)/2`
  • A simple harmonic motion is represented by : y = 5(sin 3pi t + sqrt(3) cos 3pi t)cm The amplitude and time period of the motion are :

    A
    `10 cm, (3)/(2)s`
    B
    `5 cm, (3)/(2)s`
    C
    `10 cm, (2)/(3)s`
    D
    `5cm, (2)/(3)s`
  • Similar Questions

    Explore conceptually related problems

    A simple harmonic motion is represented as x = 20 sin (2pi)t + 0.5]m find amplitude, angular frequency time period and initial phase.

    A simple harmonic motion is represented by y = 8 sin 10 pi t + 6 cos 10 pit , where is in cm and t is in sec. Calculate the amplitude time period and intial phase.

    A simple harmonic motion is represented by : y=59sin3pit+sqrt(3)cos3pit)cm The amplitude and time period of the motion by :

    A simple harmonic motion is represented by x = 12 sin (10 t + 0.6) Find out the maximum acceleration, if displacement is measured in metres and time in seconds.

    If a simple harmonic motion is represented by (d^(2)x)/(dt^(2)) + alphax = 0 , its time period is :