A particle executes SHM of time period 10 seconds. The displacment of particle at any instant is given by `: x=10 sin omegat ` (in cm). Find (i) the velocity of the body 2 s after it passes through mean position (ii) the acceleration 2 s after it passes the mean position.

Explanation

To solve the problem step-by-step, we will first break down the information given and then calculate the velocity and acceleration of the particle executing simple harmonic motion (SHM).

### Given:
- Time period \( T = 10 \) seconds
- Displacement equation: \( x = 10 \sin(\omega t) \) (in cm)

### Step 1: Calculate \( \omega \)
The angular frequency \( \omega \) is given by the formula:
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