A particle executes SHM of period `1.2 s` and amplitude `8cm`. Find the time it takes to travel `3cm` from the positive extremity of its oscillation. `[cos^(-1)(5//8) = 0.9rad]`

Explanation

Here, `T=12s,a=8cm,`
displacement , `x=8-3=5cm, t=?`
As, `x=acosomegat=acos((2pi)/(T))t`
`:. 5=8cos((2pi)/(12))t`
or `cos((pit)/(6))=(5)/(8)=0.625=cos51.3^(@)`
or `(pit)/(6)=51.3^(@) or t=(51.3^(@)xx6)/(180^(@))=1.71s`