A block lying on a horizontal table executes SHM of period 1 second, horizontally. What is the maximum amplitude for which the block does not slide if coeff. Of friction between block and surface is `0.4, pi^(2)=10. `

Explanation

To solve the problem, we need to find the maximum amplitude of a block executing Simple Harmonic Motion (SHM) on a horizontal table, given that the period of the motion is 1 second and the coefficient of friction between the block and the surface is 0.4.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Period (T) = 1 second
- Coefficient of friction (μ) = 0.4
- Acceleration due to gravity (g) = 10 m/s² (approximated)
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