A block is kept on a horizontal table. The stable is undergoing simple harmonic motion of frequency `3Hz` in a horizontal plane. The coefficient of static friciton between block and the table surface is `0.72.` find the maximum amplitude of the table at which the block does not slip on the surface.

Explanation

Max. force on the block,
F`=` mass `xx` max. acceleration `= m omega^(2)A`
Frictional force on the block `=mug`
The block will not slip on the surface of the table if `momega^(2)A= mu mg`
or `A=(mu g)/(omega^(2))=(omegag)/(4pi^(2)v^(2))=(0.72xx10)/(4xx(22//7)^(2)xx3^(2))`
`=0.02m`