A 0.2kg of mass hangs at the end of a spring. When 0.002kg more mass is added to the end of the spring, it stretches 7 cm more. If the 0.02 kg mass is removed what will be the period of vibration of the system?

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Understand the system
We have a mass \( m = 0.2 \, \text{kg} \) hanging from a spring. When we add an additional mass of \( 0.002 \, \text{kg} \), the spring stretches by \( 7 \, \text{cm} \) (or \( 0.07 \, \text{m} \)) more.

### Step 2: Write the equations for the two cases
1. For the first case (with mass \( m \)):
\[
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