If the acceleration due to gravity on the moon is one-sixth of that on the earth. What will be the change in length of a second pendulum there so that it may beat a second there? Take acceleration due to gravity on earth's surface `=9.8 ?`

Explanation

To solve the problem, we need to determine the change in length of a second pendulum when moving from Earth to the Moon, given that the acceleration due to gravity on the Moon is one-sixth that of Earth.

### Step-by-Step Solution:

1. **Understand the Time Period of a Pendulum**:
The time period \( T \) of a simple pendulum is given by the formula:
\[
T = 2\pi \sqrt{\frac{L}{g}}
...