The equation for a wave travelling in x-direction on a string is `y =(3.0cm)sin[(3.14 cm^(-1) x - (314s^(-1))t]` (a) Find the maximum velocity of a particle of the string. (b) Find the acceleration of a particle at x =6.0 cm at time t = 0.11 s.

Explanation

The eqn. of the wave is
`y=3sin[3.14x=314t]`
`upsilon=(dy)/(dt)=3cos[3.14x-314t]xx314`
`v_(max)=3xx314xx1cm//s=9.4m//s`
(b) `a=(dupsilon)/(dt)=-3 sin [3.14x-314t]xx(314)^(2)`
`=-3(314)^(2)sin[3.14xx6-314x0.11]`
`=3(314)^(2)sin(6pi-11)=Zero`