The length of a sonometer wire is `0.75m`, and density `9xx10^(3)m`. It can bear a stress of `8.1xx10^(8)N//m^(2)` without exceeding the elastice limit. What is the fundamental frequency that can be produced in the wire?

Explanation

Here, `l=0.75m, rho=9xx10^(3)kgm^(-3)`j
stress `=(f o rce)/(area)=(T)/(a)=8.1xx10^(8), T=8.1xx10^(8)a`
Mass per unit length,
`m=axx1xxrho=axx9xx10^(3)kg//m`
From `v_(1)=(1)/(2l)sqrt((T)/(m))=(1)/(2xx0.75)sqrt((8.1xx10^(8)a)/(axx9xx10^(3)))`
`=(1)/(1.5)xx3xx10^(2)=200Hz`