A 100 cm long wire of mass 40 g supports a mass of 1.6 kg as shown in figure . Find the fundamental frequency of the portion of the string between the wall and the pulley. Take `g=10m//s^(2)`.

Explanation

Here, `T=1.6kg=1,6xx10=16N`.
mass `//` length `m=(40xx10^(-3)kg)/(1m)=0.04kg//m`
`l=100-20=80cm=0.8m`
`v=(1)/(2l)sqrt((T)/(m))=(1)/(2xx0.8)sqrt((16)/(0.04))=12.5hertz`