The speed of a transverse wave going on a wire having a length 50 cm and maas 5.0 g is `80ms^(-1)` The area of cross section of the wire is `1.0mm.^2` and its Young modulus is `16 xx 10^(11) N m^(-2).` Find the extension of the wire over its natural lenth.

Explanation

Here, `upsilon=80m//s, l=50cm=(1)/(2)m`
`A=1mm^(2)=10^(6)m^(2), M=5g=5xx10^(-3)kg`
From `upsilon=sqrt((T)/(m))`,
`T=upsilon^(2)m=(80)^(2)xx(5xx10^(-3))/(1//2)=64N`
From `Y=(T//A)/(Deltal//l), Deltal=(Tl)/(AY)`
`Deltal=(64xx1//2)/(10^(-6)xx16xx10^(11))=2xx10^(-5)m =0.02mm`