A brass rod 1 metre long is firmly clampled in the middle and one end is stroked by a resined cloth. What is the pitch of the note you will hear ? Density of brass `=9gcm^(-3)` and Young's modulus of brass `=10^(12)"dyne" //cm^(2)`.

Explanation

To solve the problem, we need to determine the pitch of the note produced by a brass rod that is clamped in the middle and stroked at one end. We will follow these steps:

### Step 1: Understand the Setup
The brass rod is 1 meter long and is clamped in the middle. When one end is stroked, standing waves are formed. The clamped middle point creates a node, while the ends of the rod create antinodes.

### Step 2: Determine the Wavelength
Since the rod is clamped in the middle, the length of the rod corresponds to half of the wavelength of the standing wave. Therefore, if \( L \) is the length of the rod (1 meter), the wavelength \( \lambda \) can be calculated as:
\[
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