A hall has a volume of `10000 m^(3)`. Its total absorption is equivalentto 400sq. M of an open window. What will be the effect ona reverberation time if audience fills the hall and increases the absorption by another 400sq. Metre of an open window?

Explanation

Here, `V=10000m^(3), A_(1)=400sq.m,`
`A_(2)=400+400=800m^(2)`
`T_(1)=(0.16V)/(A_(1))=(0.16xx10000)/(400)=4sec`
`T_(2)=(0.16V)/(A_(2))=(0.16xx10000)/(800)=2sec`