Two particles are executing simple harmonic of the same amplitude (A) and frequency `omega` along the x-axis . Their mean position is separated by distance `X_(0)(X_(0)gtA). If the maximum separation between them is (X_(0)+A), the phase difference between their motion is:

Options

A. `(pi)/(3)`
B. `(pi)/(4)`
C. `(pi)/(6)`
D. `(pi)/(2)`

Answer

D

Explanation

The maximum separation between two oscillating particles in SHM is `(X_(0)+A)`.It means if at an instant one particle is at the mean position then the other particle is at the extreem right position, i.e., the phase is at the extreme right position, i.e., the phase of first particle, `ph_(1)=0` and phase of second particle , `phi_(2)=pi//2`.
`:. ` phase difference `phi_(2)-phi_(1)=(pi)/(2)-0=(pi)/(2)`