Two pearticle are oscillation along two close parallel straght lines side by side with the same frequency and amplitude They pass each other moving in opposite directions when their displacement is half of the on a stright line perpendicular to the part of the two particle The phase difference is

Options

A. 0
B. `2pi//3`
C. `pi`
D. `pi//6`

Answer

B

Explanation

In SHM, `x=a sin omega t `
When `x=A//2,` then
`(A)/(2)=Asin omegat`
or `sin omegat =(1)/(2) or omega t=(pi)/(6) or (5pi)/(6)`
`:.` Phase of 1st particle, `phi_(1)=(pi)/(6)rad`
Phase of 2nd particle, `phi_(2)=(5pi)/(6)rad`
Phase difference,
`=phi_(2)-phi_(1)=(5pi)/(6)-(pi)/(6)=(2pi)/(3)rad`