Two simple harmonic motions act on a particle. These harmonic motions are
`x=Acos (omegat+delta), y=Acos (omegat+alpha)`
When `delta=alpha+(pi)/(20,` the resulting motion is

Options

A. an ellipse and the actual motion is counter clockwise
B. an ellipse and the actual motion is clockwise
C. a circle and the actual motion is counter clockwise
D. a circle and the actual motion is clockwise

Answer

C

Explanation

`x=Acos(omegat+alpha+(pi)/(2))=-A sin (omegat+alpha)`
`:. x^(2)+y^(2)=A^(2)[sin^(2)(omegat+alpha)+cos^(2)(omegat+alpha)]=A^(2)`
which is an equation of a circle. Since y is `+ve` and `x` is `-ve` , so the circular motion is couter clockwise.