A wave, `y_( `(x, t)`)=0.03 sin pi(2t-0.01x)` tavels in a medium. Here, `x` is in metre. The instantaneous phase differenc ( in rad) between the two point separated by `25cm` is

Options

A. `pi//800`
B. `pi//400`
C. `pi//200`
D. `pi//100`

Answer

B

Explanation

`y=0.03sinpi(2t-0 .01x)`
`=0.03sin(2pit-0.01pix)` …(i)
Comparting it with the equation
`y=rsin (omegat-(2pi)/(lambda)x)`, we have
`(2pi)/(lambda)=0.01pi` or `lambda-(2)/(0.01)=200m`
Phase diff,
`Deltaphi=(2pi)/(lambda)Deltax=(2pi)/(200)xx(25)/(100)=(pi)/(400)rad`