A transverse wave is represented by the equation
`y=y_0sin.(2pi)/(lamda)(vt-x)`
For what value of `lamda`, the maximum particle velocity equal to two times the wave velocity?

Options

A. `lambda=2piy_(0)`
B. `lambda=(piy_(0))/(3)`
C. `lambda=(piy_(0))/(2)`
D. `lambda=piy_(0)`

Answer

D

Explanation

Particle velocity
`=(dy)/(dt)=[y_(0)cos((2pip)/(lambda))(upsilont-x)](2pi)/(lambda)upsilon`
`((dy)/(dt))_(max)=y_(0)(2piupsilon)/(lambda)=2upsilon`
`lambda=piy_(0)`