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Two sound sources emitting sound each of...

Two sound sources emitting sound each of wavelength `lambda` are fixed at a given distance apart. A listener moves with a velocity `u` along the line joining the two suorces. The number of beats heard by him per second is

A

`2u//lambda`

B

`u//lambda`

C

`(u)/(3lambda)`

D

`(2lambda)/(u)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how many beats the listener hears per second when moving between two sound sources emitting sound of wavelength \( \lambda \), we can follow these steps: ### Step 1: Understand the situation We have two sound sources, \( S_1 \) and \( S_2 \), emitting sound waves of wavelength \( \lambda \). The listener is moving with a velocity \( u \) along the line joining the two sources. ### Step 2: Calculate the frequency of the sound The frequency \( f \) of a sound wave is related to its wavelength \( \lambda \) and the speed of sound \( v \) in the medium by the formula: \[ f = \frac{v}{\lambda} \] Let’s denote the frequency of both sources as \( f_0 = \frac{v}{\lambda} \). ### Step 3: Determine the apparent frequency heard by the listener As the listener moves towards one source and away from the other, the apparent frequency changes due to the Doppler effect. 1. **For Source \( S_1 \)** (moving towards): The apparent frequency \( f_1 \) heard by the listener from source \( S_1 \) is given by: \[ f_1 = f_0 + \frac{u}{\lambda} \quad \text{(since the listener is moving towards the source)} \] 2. **For Source \( S_2 \)** (moving away): The apparent frequency \( f_2 \) heard by the listener from source \( S_2 \) is given by: \[ f_2 = f_0 - \frac{u}{\lambda} \quad \text{(since the listener is moving away from the source)} \] ### Step 4: Calculate the beat frequency The beat frequency \( f_b \) is the difference between the two frequencies heard by the listener: \[ f_b = |f_1 - f_2| \] Substituting the expressions for \( f_1 \) and \( f_2 \): \[ f_b = \left( f_0 + \frac{u}{\lambda} \right) - \left( f_0 - \frac{u}{\lambda} \right) \] This simplifies to: \[ f_b = \frac{u}{\lambda} + \frac{u}{\lambda} = \frac{2u}{\lambda} \] ### Final Answer The number of beats heard by the listener per second is: \[ \boxed{\frac{2u}{\lambda}} \]

To solve the problem of how many beats the listener hears per second when moving between two sound sources emitting sound of wavelength \( \lambda \), we can follow these steps: ### Step 1: Understand the situation We have two sound sources, \( S_1 \) and \( S_2 \), emitting sound waves of wavelength \( \lambda \). The listener is moving with a velocity \( u \) along the line joining the two sources. ### Step 2: Calculate the frequency of the sound The frequency \( f \) of a sound wave is related to its wavelength \( \lambda \) and the speed of sound \( v \) in the medium by the formula: \[ ...
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