The identical piano wires kept under the same tension T have a fundamental frequency of 600 Hz. The fractional increase in the tension of one of the wires which will lead to occurrence of 6 beats//s when both the wires oscillate together would be

Options

A. `0.02`
B. `0.03`
C. `0.04`
D. `0.01`

Answer

A

Explanation

Fundamental frequency `(v)` produced by a stretched string is given by
`v=(1)/(2l)sqrt((T)/(m))=ksqrt(T)` ltBRgt (As `l & m` are kept constant )
`:. (dv)/(v)=(1)/(2)(dT)/(T)`or ` (dT)/(T)=2(dv)/(v)=2xx(6)/(600)=0.02`