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A mass m=100 gram is attached at the en...

A mass `m=100 ` gram is attached at the end of a light spring which oscillates on a frictionless horizontal table with an amplitude equalt to `0.16m` and time period equal to 2 second. Initially the mass is released from rest at `t=0` and displacement `x=-0.16` metre. The expression for the displacement of mass at any time `(t)` is

A

`x-0.16cos(pit)`

B

`x=-0.16 cos (pit)`

C

`x=0.16 cos (pit+pi)`

D

`x=-0.16 cos (pit+pi)`

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The correct Answer is:
To find the expression for the displacement of the mass attached to the spring at any time \( t \), we can follow these steps: ### Step 1: Identify the parameters We have the following parameters: - Mass \( m = 100 \) grams (which is \( 0.1 \) kg) - Amplitude \( A = 0.16 \) m - Time period \( T = 2 \) seconds - Initial displacement \( x(0) = -0.16 \) m (released from rest) ### Step 2: Calculate the angular frequency The angular frequency \( \omega \) is given by the formula: \[ \omega = \frac{2\pi}{T} \] Substituting the time period: \[ \omega = \frac{2\pi}{2} = \pi \, \text{rad/s} \] ### Step 3: Write the general equation for SHM The general equation for simple harmonic motion (SHM) can be expressed as: \[ x(t) = A \sin(\omega t + \phi_0) \] where \( \phi_0 \) is the phase constant. ### Step 4: Determine the phase constant \( \phi_0 \) At \( t = 0 \), the displacement is given as \( x(0) = -0.16 \) m. Thus, we can write: \[ -0.16 = 0.16 \sin(\phi_0) \] This simplifies to: \[ \sin(\phi_0) = -1 \] The angle for which \( \sin(\phi_0) = -1 \) is: \[ \phi_0 = \frac{3\pi}{2} \, \text{rad} \] ### Step 5: Substitute \( \omega \) and \( \phi_0 \) into the equation Now we can substitute \( \omega \) and \( \phi_0 \) back into the general equation: \[ x(t) = 0.16 \sin(\pi t + \frac{3\pi}{2}) \] ### Step 6: Simplify the equation Using the sine addition formula, we can express \( \sin(\pi t + \frac{3\pi}{2}) \) as: \[ \sin(\pi t + \frac{3\pi}{2}) = -\cos(\pi t) \] Thus, the equation becomes: \[ x(t) = 0.16 \cdot (-\cos(\pi t)) = -0.16 \cos(\pi t) \] ### Final Expression The expression for the displacement of the mass at any time \( t \) is: \[ x(t) = -0.16 \cos(\pi t) \] ---

To find the expression for the displacement of the mass attached to the spring at any time \( t \), we can follow these steps: ### Step 1: Identify the parameters We have the following parameters: - Mass \( m = 100 \) grams (which is \( 0.1 \) kg) - Amplitude \( A = 0.16 \) m - Time period \( T = 2 \) seconds - Initial displacement \( x(0) = -0.16 \) m (released from rest) ...
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