Acetic acid tends to form dimer due to formation of intermolcular hydrogen bonding.
`2CH_(2)COOHhArr(CH_(3)COOH)_(2)`
The equilibrium constant for this reaction is `1.5xx10^(2)M^(-1)`in benzene solution and `3.6xx10^(-2)` in water. In benzene, monomer does not dissociate but it water, monomer dissociation simultaneously with acid dissociation constant `2.0xx10^(-5)`M. Dimer does not dissociate in benzene as well as water.
The pH of 0.1M acetic acid solution in water, considering the simultaneous dimerisation and dissociation of acid is :

Acetic acid tends to form dimer due to formation of intermolcular hydrogen bonding. 2CH_(2)COOHhArr(CH_(3)COOH)_(2) The equilibrium constant for this reaction is 1.5xx10^(2)M^(-1) in benzene solution and 3.6xx10^(-2) in water. In benzene, monomer does not dissociate but it water, monomer dissociation simultaneously with acid dissociation constant 2.0xx10^(-5) M. Dimer does not dissociate in benzene as well as water. The molar ratio of dimer to monomer for 0.1 M acetic acid in benzene is equal to :

Acetic acid tends to form dimer due to formation of intermolcular hydrogen bonding. 2CH_(2)COOHhArr(CH_(3)COOH)_(2) The equilibrium constant for this reaction is 1.5xx10^(2)M^(-1) in benzene solution and 3.6xx10^(-2) in water. In benzene, monomer does not dissociate but it water, monomer dissociation simultaneously with acid dissociation constant 2.0xx10^(-5) M. Dimer does not dissociate in benzene as well as water. The molar ration of dimer to monomer for 0.1 M acetic acid in benzene is equal to :

Acetic acid tends to form dimer due to formation of intermolcular hydrogen bonding. 2CH_(2)COOHhArr(CH_(3)COOH)_(2) The equilibrium constant for this reaction is 1.5xx10^(2)M^(-1) in benzene solution and 3.6xx10^(-2) in water. In benzene, monomer does not dissociate but it water, monomer dissociation simultaneously with acid dissociation constant 2.0xx10^(-5) M. Dimer does not dissociate in benzene as well as water. The molar ration of dimer to monomer for 0.1 M acetic acid in benzene is equal to :

Acetic acid tends to form dimer due to formation of intermolcular hydrogen bonding. 2CH_(2)COOHhArr(CH_(3)COOH)_(2) The equilibrium constant for this reaction is 1.5xx10^(2)M^(-1) in benzene solution and 3.6xx10^(-2) in water. In benzene, monomer does not dissociate but it water, monomer dissociation simultaneously with acid dissociation constant 2.0xx10^(-5) M. Dimer does not dissociate in benzene as well as water. The molar ratio of dimer to monmer for 0.1M acetic acid in water (neglecting the dissciation of acetic acid in water ) is equal to :

Acetic acid tends to form dimer due to formation of intermolcular hydrogen bonding. 2CH_(2)COOHhArr(CH_(3)COOH)_(2) The equilibrium constant for this reaction is 1.5xx10^(2)M^(-1) in benzene solution and 3.6xx10^(-2) in water. In benzene, monomer does not dissociate but it water, monomer dissociation simultaneously with acid dissociation constant 2.0xx10^(-5) M. Dimer does not dissociate in benzene as well as water. The molar ratio of dimer to monmer for 0.1M acetic acid in water (neglecting the dissciation of acetic acid in water ) is equal to :

Acetic acid tends to form dimer due to formation of intermolcular hydrogen bonding. 2CH_(2)COOHhArr(CH_(3)COOH)_(2) The equilibrium constant for this reaction is 1.5xx10^(2)M^(-1) in benzene solution and 3.6xx10^(-2) in water. In benzene, monomer does not dissociate but it water, monomer dissociation simultaneously with acid dissociation constant 2.0xx10^(-5) M. Dimer does not dissociate in benzene as well as water. The molar ratio of dimer to monmer for 0.1M acetic acid in water (neglecting the dissciation of acetic acid in water ) is equal to :

Degree of dissociation of 0.1 N CH_(3)COOH is ( Dissociation constant =1xx 10^(-5))

Find out the percentage dissociation of an acid having conc. of 10 M and dissociation constant 1.0xx10^(-3) .

Find out the percentage dissociation of an acid having conc. Of 10 M and dissociation constant 1.0xx10^(-3) .