An element `dvecl=dxhati` (where `dx=1cm`) is placed at the origin and carries a large current `i=10A`. What is the magnetic field on the Y-axis at a distance of `0.5m`?

Explanation

To find the magnetic field at a distance of 0.5 m on the Y-axis due to a current-carrying element, we can use the Biot-Savart law. Let's go through the solution step by step:

### Step 1: Define the parameters
We have:
- Current \( i = 10 \, \text{A} \)
- Element of length \( d\vec{L} = dx \hat{i} \) where \( dx = 1 \, \text{cm} = 1 \times 10^{-2} \, \text{m} \)
- The observation point on the Y-axis at a distance \( r = 0.5 \, \text{m} \)

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