The electron in a hydrogen atom circles around the proton with a speed of `2*18xx10^6ms^-1` in an orbit of radius `5*3xx10^-11m`. Calcualte (a) the equivalent current (b) magnetic field produced at the proton. Given charge on electron `1*6xx10^-19C` and `mu_0=4pixx10^-7TmA^-1`.

Explanation

To solve the problem step by step, we will calculate (a) the equivalent current and (b) the magnetic field produced at the proton.

### Step 1: Calculate the Time Period of Revolution
The time period \( T \) for one complete revolution of the electron can be calculated using the formula:
\[ T = \frac{2\pi r}{v} \]
where:
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