A long straight solid conductor of radius `5cm` carries a current of `3A`, which is uniformly distributed over its circular cross-section. Find the magnetic field induction at a distance `4cm` from the axis of the conductor. Relative permeability of the conductor=1000.

Explanation

To find the magnetic field induction at a distance of 4 cm from the axis of a long straight solid conductor carrying a uniformly distributed current, we can follow these steps:

### Step 1: Define the parameters
- **Radius of the conductor (a)** = 5 cm = 0.05 m
- **Current (I)** = 3 A
- **Distance from the axis (r)** = 4 cm = 0.04 m
- **Relative permeability (μr)** = 1000
- **Permeability of free space (μ₀)** = \(4\pi \times 10^{-7} \, \text{T m/A}\)
...