A solenoid of length `0*5m` has a radius of `1cm` and is made up of `500` turns. It carries a current of `5A`. What is the magnitude of the magnetic field inside the solenoid?

Explanation

To find the magnitude of the magnetic field inside a solenoid, we can use the formula:

\[ B = \mu_0 n I \]

where:
- \( B \) is the magnetic field inside the solenoid,
- \( \mu_0 \) is the permeability of free space (\( 4\pi \times 10^{-7} \, \text{T m/A} \)),
- \( n \) is the number of turns per unit length of the solenoid,
...