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Magnetic field applied on a cyclotron is...

Magnetic field applied on a cyclotron is `0*7T` and radius of its dees is `1*8m`. What will be the energy of the emergent protons in `MeV`? Mass of proton`=1*67xx10^-27kg`.

Text Solution

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`E=(q^2B^2r^2)/(2m)=((1*6xx10^-19)^2xx(0*7)^2xx(1*8)^2)/(2xx1*67xx10^-27)J=((1*6xx10^-19)^2xx(0*7)^2xx(1*8)^2)/(2xx1*67xx10^-27xx1*6xx10^-13)MeV`
`=76MeV`
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Knowledge Check

  • The oscillating frequency of a cyclotron is 10 MHz . If the radius of its Dees is 0.5 m , the kinetic energy of a proton which is accelerated by the cyclotron is

    A
    `10.2 Me V`
    B
    `2.55 Me V`
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    D
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