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An ammeter of resistance 0*80Omega can m...

An ammeter of resistance `0*80Omega` can measure current upto `1*0A`.
(a) What must be the value of shunt resistance to enable the ammeter to measure current upto `5*0A`?
(b) What is the combined resistance of the ammeter and the shunt?

Text Solution

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Here, `G=0*80Omega`, `I_g=1*0A`, `I=5*0A`, `S`.
(a) `S=(I_gG)/(I-I_g)=(1xx0*8)/(5-1)=0*2Omega`
(b) Combined resistance of shunt and ammeter `=(GS)/(G+S)=(0*8xx0*2)/(0*8+0*2)=0*16Omega`
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