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A proton enters a magnetic field of flux...

A proton enters a magnetic field of flux density `2*5T` with a speed of `1*5xx10^7ms^-1` at an angle of `30^@` with the field, Find the force on the proton.

Text Solution

Verified by Experts

Here, `q=e=1*6xx10^(-19)C`
`B=2*5T`, `v=1*5xx10^7ms^-1`, `theta=30^@`
`F=qvBsintheta=(1*6xx10^(-19))xx(1*5xx10^7)xx25xxsin30^@`
`=3xx10^(-12)N`
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