Home
Class 12
PHYSICS
An electron travels in a circular path o...

An electron travels in a circular path of radius `20cm` in a magnetic field `2xx10^-3T` (i) Calculate the speed of the electron (ii) What is the potential difference through which the electron must be accelerated to acquire this speed? Charge of electron `=1*6xx10^(-19)C`. Mass of electron `=9xx10^(-31)kg`.

Text Solution

AI Generated Solution

To solve the problem step by step, we will break it down into two parts as indicated in the question. ### Given Data: - Radius of the circular path, \( r = 20 \, \text{cm} = 0.2 \, \text{m} \) - Magnetic field strength, \( B = 2 \times 10^{-3} \, \text{T} \) - Charge of the electron, \( q = 1.6 \times 10^{-19} \, \text{C} \) - Mass of the electron, \( m = 9 \times 10^{-31} \, \text{kg} \) ...
Promotional Banner

Topper's Solved these Questions

  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Conceptual Problems (d)|2 Videos
  • MAGNETIC EFFECT OF CURRENT AND MAGNETISM

    PRADEEP|Exercise Very Short Answer Questions (a)|2 Videos
  • ELECTROSTATICS

    PRADEEP|Exercise ASSERTION-REASON TYPE QUESTIONS|2 Videos
  • OPTICS

    PRADEEP|Exercise Multiple choice questions|1 Videos

Similar Questions

Explore conceptually related problems

An electron travels on a circular path of radius 10 m in a magnetic field of 2 xx 10^(–3) T. Calculate the speed of electron. What is the potential difference through which it must be accelerated to acquire this speed?

An electron is accelerated under a potential difference of 182 V. the maximum velocity of electron will be (Given, charge of an electron is 1.6xx10^(-19)C ms^(-1) and its mass is 9.1xx10^(-31)kg )

An electron is revolving in a circular path of radius 2xx10^(-10) m with a speed of 3xx10^(6) m/s. The magnetic field at the centre of circular path will be-

An X-ray tube operates at 20k V . Find the maximum speed of the electron strinking the anode , given the charge of electron is 1.6 xx 10^(-19) coulomb and mass of electron is 9 xx 10^(-31) kg .

Calculate the gyro magnetic ratio of electron (given 1.6 xx10^(-19) C, m_r=9.1xx10^(-3) kg )

An electron moves along a circular path of radius 10 cm. If the centripetal acceleration is 4xx10^(11) m//s^(2) , then its linear speed is

The Velocity of electrons accelerated bt potential difference of 1xx10^(4) V (the charge of the electron is 1.6xx10^(-19) C and mass is 9.11xx10^(-31) kg) is

A chamber is maintained a uniform magnetic field of 5xx10^-3T . An electron with a speed of 5xx10^7ms^-1 enters the chamber in a direction normal to the field. Calculate (i) radius of the path (ii) frequency of revolution of the electron. Charge of electron =1*6xx10^(-19)C , Mass of electron =9*1xx10^(-31)kg

An electron in a television picture tube travels at 3xx10^(7) m/s. It is subjected to a transverse magnetic field of 2xx10^(-3)Wb//m^(2). What is the magnitude of the lateral foce acting on the electron, due to the action of the magnetic field ? Charge on the electron =-1.6 xx10^(-19) C.