An electron of energy `2000eV` describes a circular path in magnetic field of flux density `0*2T`. What is the radius of the path? Take `e=1*6xx10^(-19)C`, `m=9xx10^(-31)kg`.

Explanation

To solve the problem of finding the radius of the circular path of an electron in a magnetic field, we will follow these steps:

### Step 1: Convert the energy from electron volts to joules
The energy of the electron is given as \( 2000 \, \text{eV} \). We know that:
\[ 1 \, \text{eV} = 1.6 \times 10^{-19} \, \text{J} \]
Thus, the energy in joules is:
\[
E = 2000 \, \text{eV} \times 1.6 \times 10^{-19} \, \text{J/eV} = 3.2 \times 10^{-16} \, \text{J}
...