In a cycloton, the protons are to be accelerated with a magnitude field of magnitude `1*5T`. How rapidly should the electric field between the dees be reversed? Mass and charge of proton are `1*67xx10^(-27)kg` and `1*6xx10^(-19)C` respectively.

Explanation

Here, `B=1*5T`,
`m=1*67xx10^(-27)kg, q=1*6xx10^(-19)C`
Time taken by proton to complete a semicircular path in a dee of cyclotron is
`t=(pim)/(Bq)=(3*14xx(1*67xx10^(-27)))/(1*5xx(1*6xx10^(-19)))`
`=2*18xx10^-8s`
It means, the direction of electric field should be reversed after every `2*18xx10^-8s`.
The frequency of the applied electric field is
`v=(1)/(2t)=(1)/(2xx2*18xx10^-8)=2*29xx10^7Hz`