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A long straight conductor C carrying a c...

A long straight conductor C carrying a current of `3A` is placed parallel to a short conductor D of length `5cm`, carrying a current `4A`. The two conductors are `10cm` apart. Find (i) the magnetic field due to C at D. (ii) The approximate force on D.

Text Solution

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(i) Magnetic field due to C at D is
`B=(mu_0)/(4pi)(2I)/(r)=10^-7xx(2xx3)/(0*10)=6xx10^-6T`
(ii) Force on D, `F=BI_1lsintheta`
`=(6xx10^-6)xx4xx(5xx10^-2)xxsin 90^@`
`=1*2xx10^-6N`
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