A horizontal wire `0*2m` long carries a current of `4A`. Find the magnitude and direction of the magnetic field, which can support the weight of the wire. Given, the mass of the wire is `3xx10^-3kg//m`, `g=10ms^-2`.

Explanation

To solve the problem step by step, we will follow the reasoning outlined in the video transcript.

### Step 1: Calculate the mass of the wire
The mass per unit length of the wire is given as \(3 \times 10^{-3} \, \text{kg/m}\). The length of the wire is \(0.2 \, \text{m}\).

\[ \text{Mass of the wire} = \text{mass per unit length} \times \text{length} = 3 \times 10^{-3} \, \text{kg/m} \times 0.2 \, \text{m} = 6 \times 10^{-4} \, \text{kg} \]
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